3x^2+7x+10=8

Solution for 3x^2+7x+10=8 equation:

3x^2+7x+10=8

We move all terms to the left:

3x^2+7x+10-(8)=0

We add all the numbers together, and all the variables

3x^2+7x+2=0

a = 3; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·3·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*3}=\frac{-2}{6}
=-1/3
$